Lesson 9: Uniformly accelerated motion in 1D
Simulation
Video Lesson
Lesson objective
Dear learners,
At the end of the lesson you will be able to
- Explain a uniformly accelerated motion in 1D;
- Explain the difference between average velocity and instantaneous velocity; and
- Solve problems involving average velocity, instantaneous velocity and acceleration
Brainstorming Question
- How will it be possible for a car to move but not accelerating?
Key Terms and Concepts
- Acceleration
- Average Acceleration
- Instantaneous Acceleration
- Zero Acceleration
- Retardation
is the rate of change of velocity or change in velocity per unit time.
the total change in velocity in the given interval divided by the total time taken for the change.
The ratio of change in velocity during a given time interval such that the time interval goes to zero.
When the velocity is zero, it is termed
When an object’s velocity decreases with time,
LESSON Presentation
Acceleration
- Acceleration :- is the rate of change of velocity or change in velocity per unit time.
- An object is said to accelerate when its velocity changes in magnitude, in direction or both in magnitude and direction.
- Acceleration is a vector quantity, and
- The SI unit of acceleration is m/s. 2
- Negative acceleration may or may not be deceleration, and deceleration may or may not be considered negative acceleration.
- If the velocity and acceleration have the same sign whether positive or negative it is speeding up.
- If the velocity and acceleration have different signs, then the object is slowing down.
- Acceleration can be positive, negative or zero.
- When an object’s velocity increases with time, it can be termed Positive Acceleration.
- When an object’s velocity decreases with time, it can be termed Negative Acceleration or Retardation.
- When the velocity is zero, it is termed Zero Acceleration.
- A few examples of acceleration are the falling of an apple, the moon orbiting around the earth, or when a car is stopped at the traffic lights.
- Through these examples, we can understand that when there is a change in the direction of a moving object or an increase or decrease in speed, acceleration occurs.
- $accleration=\frac{\left( final velocity \right)-\left( initial velocity \right)}{time}$
- $accleration=\frac{Change in velociy}{time}$
- $\overrightarrow{a}=\frac{\Delta V}{t}$
Where,
- a = is the acceleration in m.s-2
- vf =s the final velocity in m.s-1
- vi = is the initial velocity in m.s-1
- t = is the time interval in s
- Δv = is the small change in the velocity in m.s-1

Figure 3.1 A car slowing down and speeding up
Average acceleration
The average acceleration :- the total change in velocity in the given interval divided by the total time taken for the change.
For a given interval of time, it is denoted as $\overrightarrow{a}$
Mathematically,
$\overrightarrow{a}=\frac{\Delta V}{t}=\frac{V_{f}-V_{i}}{t_{f}-t_{i}}$
Examples 3.1
A truck accelerates from 6 m/s to 10 m/s in a time period of 10 s. What will be its acceleration?
Solution
- Initial Velocity (u) = 6 m/s
- Final Velocity (v) = 10 m/s
- Time taken (t) = 10 s
Using the Acceleration Formula,
Acceleration a = (v – u) / t
a = (10 m/s – 6 m/s) / 10 s
a = 0.4 m/s2
Thus, the acceleration of the truck is calculated as 0.4 m/s2.
Instantaneous Acceleration
Instantaneous acceleration:-is the rate at which velocity changes using both speed and direction with respect to time such that the time interval goes to zero.

Example 3.2
The position of a particle is x(t) = 2t + 0.7t³ m. Find the instantaneous acceleration at t= 3 sec?
Solution
x(t) = 2t + 0.7t³
So,
v(t) = dx(t)/dt = 2+2.1t² m/s
Now,
a(t) = dv(t)/dt = 4.2t m/s²
Therefore,
At t = 3 sec instantaneous acceleration is;
4.2t = 4.2 × 3= 12.6 m/s² (Answer)
Examples 3.3
A particle is in motion and is accelerating. The position of the velocity is v(t) = 10t – 3t² m/s
- Find the functional form of acceleration.
- Find the instantaneous velocity at t= 1,3,4,5 s
- Find the instantaneous acceleration at t= 1,3,4,5s.
- Analyze the results of © in terms of acceleration and velocity vectors directions.
Solution
v(t) = 10t – 3t² m/s
- a(t) = dv(t)/dt = 10 – 6t m/s²
- v(1s) = 7 m/s
v(3s) = 3 m/s
v(4s) = -8 m/s
v(5s) = -25 m/s
a(1s) = 4 m/s²
Motion with Constant Acceleration
- If an equal amount of velocity increases in equal intervals of time, then the object is said to be in uniform acceleration motion
- In this case, the average acceleration equals the instantaneous acceleration, and the average velocity is the average of the initial and final velocities.
$V_{av}=\frac{V_{i}+V_{f}}{2}$
- If the velocity of the object changes by unequal amounts in equal intervals of time, the object is said to be non-uniform acceleration.