Lesson 7: Irrational Numbers
Lesson Objectives
Dear learner,
At the end of this lesson, you will be able to:
- Classify various decimals as either terminating, repeating, or irrational by analyzing their patterns
- Distinguish between rational and irrational numbers by analyzing given examples, including square roots and decimals, to determine if they can be expressed as fractions or not.
- Apply operations involving irrational numbers, such as addition, subtraction, multiplication, and division, and simplify the results to their most reduced forms.
- Locate and plot irrational numbers such as $2\sqrt{2}$ and $3\sqrt{3}$ on a number line by estimating their approximate positions relative to known rational numbers.
Key Terms
- Irrational numbers
- Non-repeating and non terminating decimals
Brainstorming Questions
Here are three real-life brainstorming questions related to the concepts of rational and irrational numbers, tailored to Ethiopian daily activities:
1. “When buying fruits from a market in Ethiopia, you notice that some fruits are sold by weight, and the prices are given as decimals. How can you determine if a price expressed in decimal form is a rational number? For example, if apples cost 0.75 birr per gram, is this price a rational number? Why or why not?”
Explanation:
To determine if a price expressed as a decimal is a rational number, check if it can be expressed as a fraction. In this case, 0.75 can be written as $\frac{75}{100}$, which simplifies to $\frac{3}{4}$. Since it can be expressed as a fraction of two integers, it is a rational number. Prices in decimal form at markets are typically rational because they can be converted into fractions representing their exact values.
2. “When constructing traditional Ethiopian houses, measurements are often made using irrational numbers. For instance, if you need to measure the diagonal of a square room with each side of 5 meters, the length of the diagonal is $\sqrt{50}$ meters. How would you simplify $\sqrt{50}$ to use in practical construction, and why is $\sqrt{50}$ an irrational number?”
Explanation:
To simplify $\sqrt{50}$, factor it into $\sqrt{25 \times 2}$ which equals $5\sqrt{2}$. This simplification helps in practical applications by giving a more manageable number. $\sqrt{50}$ is irrational because it cannot be expressed as a simple fraction of two integers. The decimal representation of $\sqrt{50}$ is non-repeating and non-terminating, thus making it an irrational number.
3.1. Irrational numbers
Note
Recall that, terminating and repeating decimals can be classified as rational numbers because they can be expressed as fractions of numbers.
Definition:
Irrational numbers are:
- Numbers that cannot be expressed as a fraction $\frac{a}{b}$, where $a$ and $b$ are integers. Their decimal expansions are non-repeating and non-terminating, such as $(\pi)$ and $(\sqrt{2})$.
- Neither repeating nor terminating numbers.
For example:
0.121221222122…., 3.125436745897…., -12.020220222022…., ……….
$\sqrt[n]{x}$, where x is not a perfect $n^{th}$ exponent number.
$\sqrt{10}$, $\sqrt[3]{16}$, $\sqrt[4]{8}$, ……
- $\pi$ as itself is irrational number. But, the rational approximation numbers 3.14 and $\frac{22}{7}$ are rational numbers.
Example 1:
Determine whether each of the following numbers is rational or irrational.
a. $\sqrt{36}$ b) $\sqrt{46}$ c) $\sqrt{0.09}$ d) $\sqrt0.16}$
Solution:
a) $\sqrt{36}$ = $\sqrt{6*6}$ = 6. Thus, $\sqrt{36}$ is rational number.
b) $\sqrt{23*2}$ it can not be written out of radical. Thus, $\sqrt{46}$ is irrational number.
c) $\sqrt{0.09}$ = $\sqrt{(0.3 * 0.3)}$ = 0.3. Thus $\sqrt{0.09}$ is rational number.
d) $\sqrt{0.16}$ = $\sqrt{0.4*0.4}$ = 0.4. Thus $\sqrt0.16}$ is rational number.
i. Locating irrational number on the number line
Example 2:
Locate $\sqrt{2}$ on the number line.
Solution:
Draw a number line. Label an initial point 0 and points 1 unit long to the right and left of 0. Construct a perpendicular line segment 1 unit long at 1.

Example 3:
Locate 1, $\sqrt{2}$, $\sqrt{3}$, and 2, on the number line.
Solution:

3.2 Operations on irrational numbers
The paragraph is informing the reader that in section 2.3.1 of the material, they have learned about what an irrational number is and how it is represented on the number line. The paragraph then states that in the upcoming section, the focus will be on discussing the operations of addition, subtraction, multiplication, and division involving irrational numbers.
When $a > 0, \;and\; b > 0 $, then $\sqrt{a} \times \sqrt{b} = \sqrt{ab}$.
Example 4:
Find the solution for each of the following equations/problems.
a. $\sqrt{2} \times \sqrt{7}$
b. $[5\sqrt{3} \times \sqrt{5}]$
c. $( \frac{3}{\sqrt{7}} \times \frac{11}{\sqrt{3}})$
d. $( (\sqrt{5} + \sqrt{2})(\sqrt{6} – \sqrt{5}))$
Solution:
a) $\sqrt{2} \times \sqrt{7} = \sqrt{2 \times 7} = \sqrt{14}.$
b. $5\sqrt{3} \times \sqrt{5} = 5\sqrt{3\times 5}= 5\sqrt{15}$.
c. $\frac{3}{\sqrt{7}} \times \frac{11}{\sqrt{3}} = \frac{3 \times 11}{\sqrt{7 \times 3}}= \frac{33}{\sqrt{21}}$.
d) $\sqrt{5} + \sqrt{2})(\sqrt{6} – \sqrt{5}) = ( \sqrt{5} \times \sqrt{6} – \sqrt{5}\times \sqrt{5} + \sqrt{2} \times \sqrt{6} – \sqrt{2} \times \sqrt{5})$
$= (\sqrt{30} – \sqrt{25} + \sqrt{12} – \sqrt{10})$
$ = (\sqrt{30} – 5 + 2\sqrt{3} – \sqrt{10})$.
Note:
When $a > 0$ and $b > 0 $, then $\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}$.
Examples 5:
Calculate a. $-\frac{\sqrt{8}}{\sqrt{2}}$ b) $\sqrt{\frac{9}{4}}$.
Solution:
a. $-\frac{\sqrt{8}}{\sqrt{2}}$ = $-\sqrt{\frac{8}{2}}$ = $-\sqrt{4}$ = $-2$
b. $\sqrt{\frac{9}{4}}$ = $\frac{\sqrt{9}}{\sqrt{4}}$ = $\frac{3}{2}$.
Note:
When $a > 0$, and $b > 0 $, then $a\sqrt{b}$ = $\sqrt{a^{2}b}$, $\sqrt{a^{2}b} = a\sqrt{b}$.
Example 6:
Convert each of the following in $\sqrt{a}$ form. a) $3\sqrt{5}$ b) $-4\sqrt{7}$.
Solution:
a. $3\sqrt{5}$ = $\sqrt{3^{2}\ast 5}$ = $\sqrt{9\ast 5}$ = $\sqrt{45}$
b. $-4\sqrt{7}$ = $ – \sqrt{4^{2}\ast 7}$ = $ – \sqrt{16\ast 7}$ = $-\sqrt{112}$.
Example 7:
Simplify each of the following.
a. 0.454554555 … + 0.32322322 … c) $\sqrt{18} + \sqrt{50}$.
b. 0.363663666 … − 0.141441444 … d) $\sqrt{48} – \sqrt{27}$.
Solution:
a) 0.454554555 … + 0.32322322 … = 0.777777……..
b) 0.363663666 … − 0.141441444 … = 0.22222……
c) $\sqrt{18} + \sqrt{50}$ = $\sqrt{3^{2}\ast 2} + \sqrt{5^{2}\ast 2}$ = $3\sqrt{2} + 5\sqrt{2}$ = $8\sqrt{2}$
d) $\sqrt{48} – \sqrt{27} = \sqrt{4^{2}\ast 3} – \sqrt{3^{2}\ast 3} = 4\sqrt{3} – 3\sqrt{3} = 1\sqrt{3} = \sqrt{3}$
i. Conversion Between Forms:
Irrational numbers can sometimes be expressed in simplified radical form. For instance:
- $(3\sqrt{5} = \sqrt{3^2 \times 5} = \sqrt{45})$.
- $(-4\sqrt{7} = -\sqrt{4^2 \times 7} = -\sqrt{112})$.
ii. Simplifying Expressions:
Addition and Subtraction:
Combine terms under the square root or simplify radicals to find the result. For example, $(\sqrt{48} – \sqrt{27} = 4\sqrt{3} – 3\sqrt{3} = \sqrt{3})$.
Example 8:
Determine whether each number is rational or irrational:
$a. \sqrt{36}$ (rational, equals 6)
$b.\sqrt{46}$ (irrational, cannot be simplified to a fraction)
$c. \sqrt{0.09}$ (rational, equals 0.3)
$d. \sqrt{0.16}$ (rational, equals 0.4)